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x^2+40x+76=0
a = 1; b = 40; c = +76;
Δ = b2-4ac
Δ = 402-4·1·76
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-36}{2*1}=\frac{-76}{2} =-38 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+36}{2*1}=\frac{-4}{2} =-2 $
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